The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>
In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:
f(x) = x² - 5 Given
f' = [(x + h)² - 5 - x² + 5] / h Definition of derivative
(x² + 2 · x · h + h² - 5 - x² + 5) / h Perfect square trinomial
(2 · x · h + h²) / h Associative, commutative and modulative properties / Existence of additive inverse
2 · x + h Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse
2 · x h = 0 / Result
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
To learn more on derivatives: brainly.com/question/25324584
#SPJ1
Answer:
Additive inverse : j(x) = -x + 24
Multiplicative inverse : k(x) = 1/x-24
Step-by-step explanation:
I literally have no idea how, I got this answer off of quizlet :) have a good day.
=4(4x+2y+x-y)
=4*4x+4*2y+4*x-4*y
=16x+8y+4x-4y
=16x+4x+8y-4y
=20x+4y
donc la bonne reponse est la 3
4(5x+y)*
=4*5x+4*y
=20x+4y
Division is basically
x divided by y=x/y so
18 divided by 2/3=
we want the bottom number to be =1 so we multiply 2/3 by 3/2 to make it 1 (or 6/6=1), but we have to multiply the top number by 3/2 also so that we don't change the fraction and make our work useless so
the answe ris 27
Answer:w40
Step-by-step explanation:
w15/w5 = w10
(w10)^4 = w40
