A- 1000 m/s2 Xi-0m Xf-0.75m Vf-?
1 answer:
Answer:
The final velocity of the object is, = 27 m/s
Explanation:
Given,
The acceleration of the object, a = 1000 m/s²
The initial displacement of the object, = 0 m
The final displacement of the object, = 0.75 m
The initial velocity of the object will be, = o m/s
The final velocity of the object, = ?
The average velocity of the object,
v = ( -
)/ t
= 0.75 / t
The acceleration is given by the relation
a = v / t
1000 m/s² = 0.75 / t²
t² = 7.5 x 10⁻⁴
t = 0.027 s
Using the I equation of motion,
= u + at
Substituting the values
= 0 + 1000 x 0.027
= 27 m/s
Hence, the final velocity of the object is, = 27 m/s
You might be interested in
Answer:
Velocity of the ball after 3.04 (s) = 29.79 (m/s)
Explanation:
From the free fall movement we have the following formulas: and
, First we need to find the height to time iqual to 3.04 s using the formula:
and remember that golf ball was released from the rest (Vo= 0 (m/s)) so
, we get: h = -45.28 (m) with the height that we have got, now the velocity of the ball is calculate using
solving for Vf, we get:
replacing the values given
, so we get: Vf = 29.79 (m/s).