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2 years ago

Beau and Bella's grandmother gave them a pack of 54 pencils for school. How many pencils will each get?

Mathematics

2 answers:

Firdavs [7]2 years ago

7 0

27 pencils each because 54 divided by 2 is 27

rusak2 [61]2 years ago

4 0

27 because you have to divide 54 pencils by two people

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Please Answer!!! how do the graphs of (x) = x^2 and g (x)= 3/4 x^2? relate?

Hitman42 [59]

C bc it has the most sense

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2 years ago

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Two business partners, Alan and Rob, invested money in their business at a ratio of 6 to 7. Bob invested the greater amount. The

Verdich [7]

Answer:

180 Alan, 210 Rob

Step-by-step explanation:

6+7= 13

390÷13= 30

30×6=180 =Alan

30××7=210 =Rob

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2 years ago

Will give brainliest and thanks

Maru [420]

Answer:

y = -3x - 3

Step-by-step explanation:

First, determine the slope of the red line. As we move from (0, 3) to (1, 0),

x increases by 1 and y decreases by 3. Hence, the slope, m, is

m = rise / run = -3 / 1, or m = -3.

The desired new line, parallel to the red line, has the same slope as the red line: m = -3.

The equation for this new line is y - k = m (x - h), where (h, k): (-1, 0):

We get y - 0 = -3 (x + 1), or y = -3x - 3.

Check: Does this line go thru the given point (-1, 0)?

Is 0 = -3(-1) - 3 true? Yes, it is true.

6 0

2 years ago

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function $f(x)=(x^{2},4x,z^{2})$ and curve C is ellipse of equation

$16x^{2} + 4y^{2} = 3$

Theory: Stokes Theorem is given by:

$I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx$

Where, Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Also, f(x) = (F1,F2,F3)

$\hat{N} = grad(g(x))$

Using Stokes Theorem,

Surface is given by g(x) = $16x^{2} + 4y^{2} - 3$

Therefore, tex]\hat{N} = grad(g(x))[/tex]

$\hat{N} = grad(16x^{2} + 4y^{2} - 3)$

$\hat{N} = (32x,8y,0)$

Now, $f(x)=(x^{2},4x,z^{2})$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]$

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

$I= \int \int\limits {Curl f\cdot \hat{N} } \, dx$

$I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx$

I=0

Thus, The circulation of the field f(x) over curve C is Zero

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2 years ago

If a rhombus is a square, then it is a rectangle ( True or False )

nirvana33 [79]

False i believeeee :p

6 0

2 years ago

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