In this item, we are informed that the order of the entries does not matter in determination the number of ways in which the Archie can choose for his party. Because the arrangement or order is not important, this type of problem uses the concept of COMBINATION.
The equation for combination is,
nCr = n!/((n - r)!(r!))
nCr is read as "combination of n taken r".
Substituting the known values to the equation,
15C6 = 15! / ((15 - 6)!(6!))
= 5005
Hence, there are 5005 ways in which Archee can choose the 6 entrees for his party.
Hi <span>Bladen8960
So the only numbers that matter are the classes. So let's write it out 30, 60, 60, 60, 60, 60, 60, 60, 60, 70, 100, 100, 100, 100. OK so average is mean so to find mean we add all the classes then divide by how many their are so, adding them all together we get 880 students can go into each classroom so now we divide that by 14 how many classes their are which gives us about 62.
If I'm wrong I'm sorry but I hope this helps!</span>
Answer:
E1 and E2 are not mutually exclusive events. They have outcomes in common because a winning number can be both red and odd.
Step-by-step explanation:
EDMENTUM
Answer:
82 grams
Step-by-step explanation:
each rubber band weighs 3 grams because when 2 bands were added to 88 grams it went up 6 grams and six divided by 2 equals 3.
