<h3><u>Answer;</u></h3>
Evolutionary patterns observed in the fossil record are consistent with evolutionary processes occurring today.
<h3><u>Explanation;</u></h3>
- Three spine stickleback is a model organisms for studies in evolution because; Stickleback fish are small and have short generation times. These two characteristics make them easy to keep in a lab and useful for conducting genetic studies, since researchers can follow several generations of fish in a relatively short time.
- Also, stickleback fish populations occur throughout the Northern Hemisphere in a wide range of environments, so researchers can compare different populations and study how they have changed over time in response to different environmental pressures.
Answer:
A bacterial cell is filled with cytoplasm in which molecules of DNA float freely as they do not have a nucleus. In addition to this the only membrane bound organelle is the ribosome.
Explanation:
Answer:
100x − 200y = 600 and x + y = 12
Explanation:You can win the quiz show with 600 points. Remember that correct responses are worth 100 points and incorrect responses are worth -200 points. So, you need your total points from each correct response, x, minus your total points for each incorrect response, y, to equal 600:
100x − 200y = 600.
If you only respond to 12 questions, you need the total number of correct responses, x, plus the total number of incorrect responses, y, to equal 12:
x + y = 12.
Together, these two equations describe one way you can win.
In living organisms DNA<span> does not </span>usually<span> exist as a single molecule, but ...... Levene suggested that </span>DNA<span>consisted of </span>a string of nucleotide<span> units</span>
<h2>Mark and recapture method</h2>
Explanation:
Mark and recapture is a technique to measure the size of a population before fishing and hunting season;commonly used by fish and wildlife managers
- It involves the marking of number of individuals in a natural population,returning them to that population followed by recapturing some of those as a basis for estimating the size of the population at the time of marking and release
- Population size can be estimated as(N)=M*T/R
here,M=initially marked;T=total in sample second;R=marked recaptures
There are certain assumptions to this method
- Population is assumed to be closed which means no new individuals were born or immigrated into the population and none died or emigrated from the population
- The chance for each individual in the population to be caught are equal and constant for both the initial marking period and the recapture period
- One of the assumption of this method is that sufficient time must be given between the initial marking period and recapture period for all marked individuals but time period should not be very long
- Animals do not lose their mark
The tags in the given question were estimated a year there is a chance that old marked tags population might have died or emigrated(the longer the time interval the greater the chance) and hence it becomes an "open" population which violates the first law
If proportion of population changes then marked recapture method formula won't turn out be applicable
