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2 years ago

Can someone help me out?

Mathematics

1 answer:

Alexeev081 [22]2 years ago

7 0

Answer: factorise the equation 49x^2+70x+25

Step-by-step explanation:

49x^2+70x+25

(7x)^2+2*7x*5+(5)^2

(7x+5)(7x+5)

therefore the sides of the square are (7x+5)(7x+5)

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Answers this and ill give brainliest

bogdanovich [222]

Answer:

Late fees have been said to encourage returns, thus putting library materials back into circulation for others to use

Step-by-step explanation:

5 0

2 years ago

4(2x-3)=0.2(x+5)÷5.72

rusak2 [61]

Answer:

x=1.528534

Explanation:

Simplify both sides of equation

4(2x-3)=0.2(x+5)/5.72

(4)(2x)+(4)(−3)=0.034965x+0.174825(Distribute)

8x+−12=0.034965x+0.174825

8x−12=0.034965x+0.174825

Step 2: Subtract 0.034965x from both sides.

8x−12−0.034965x=0.034965x+0.174825−0.034965x

7.965035x−12=0.174825

Step 3: Add 12 to both sides.

7.965035x−12+12=0.174825+12

7.965035x=12.174825

Step 4: Divide both sides by 7.965035.

7.965035x/7.965035=12.174825/7.965035

x=1.528534

4 0

2 years ago

The time t required to do a job varies inversely with the number of people p who work on the job. If it takes 3 hours for 16 peo

Anna71 [15]

Let the hall be A=1. For 3 hours 16 people can decorate the hall. Then P1=A\(t1.number people1) P=1/48. That is for 1 person. You have 24 people to decorate the same hall. Their P2 will be (1/48).24=1/2. t2=A/P2=2 hours

6 0

2 years ago

6.A = 23 × 3 × 5 B = 22 × 3 × 52

frez [133]

Given:

The two numbers are

$A=23\times 3\times 5$

$B=22\times 3\times 52$

To find:

The highest common factor (HCF) of A and B

Solution:

We have,

$A=23\times 3\times 5$ ...(i)

$B=22\times 3\times 52$

All the factors of A are prime but the factors of B are not prime. So, it can be written as

$B=2\times 11\times 3\times 13\times 2\times 2$ ...(ii)

From (i) and (ii), it is clear that 3 is the only common factor of A and B. So,

$HCF(A,B) = 3$

Therefore, the highest common factor (HCF) of A and B is 3.

6 0

2 years ago

Suppose a baseball team has 14 players on the roster who are not members of the pitching staff. Of those 14 players, assume that

Nadusha1986 [10]

Answer: Our required probability would be 0.70.

Step-by-step explanation:

Since we have given that

Number of players = 14

Number of players have recently taken a performance enhancing drug = 3

Number of players have not recently taken a performance enhancing drug = 14-3=11

Number of members chosen randomly = 5

We need to find the probability that at least one of the tested players is found to have taken a performance enhancing drug.

P(Atleast 1) = 1 - P(none is found to have taken a performance enhancing drug)

So, P(X≥1)=1-P(X=0)

$P(X\geq 1)=1-^5C_0(\dfrac{11}{14})^5\\\\P(X\geq 1)=1-(0.786)^5\\\\P(X\geq 1)=0.70$

Hence, our required probability would be 0.70.

7 0

2 years ago