We are given original equation: 
We need to find the enter and radius of a circle using the completing the square method.
The steps are as following :
Step 1 [original equation]: x^2 − 10x + y^2 + 12y = 20 .
Step 2 [group like terms]: (x^2 − 10x) + (y^2 + 12y) = 20
Step 3 [complete the quadratics]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 20 + (25 + 36).
Step 4 [simplify the equation]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 64.
Step 5 [factor each quadratic]: (x − 5)^2 + (y + 6)^2 = 8^2
Step 6 [identify the center and radius]: Center = (5, −6) Radius = 8.
<h3>Step 6 is incorrect.</h3><h3>The center should be (5,-6).</h3><h3> Replace − 5 with + 5 and replace + 6 with − 6.</h3>
Answer:
I got $7.75.
Step-by-step explanation:
66.85-4.85=62
62/8=7.75.
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</span>
Answer:
2
Step-by-step explanation:
(x)(y) = k Inverse relationship
(4)(3) = k
12 = k
(6)(y) = 12
y = 2
Answer:
pre-image XYZ is X (2, 2), Y (6, 0), Z (1, -1)
The above is the second option in your question.
Step-by-step explanation:
a triangle has points X' (-2, 2), Y' (0, 6), Z' (1, 1)
To rotate the above triangle -90° about the origin you invert the x & y values and change the sign on the new y value.
pre-image XYZ is X (2, 2), Y (6, 0), Z (1, -1)
