Correct answer for the above question is - option B. 86°
<u>Step-by-step explanation:</u>
Given:
∠NOP = 24°
∠NOQ = 110°
∠NOP and ∠POQ are adjacent angles
To Find:
∠POQ = ?
Solution:
Hereby, we can say that ∠POQ lies between line OQ and ON as given (∠NOP and ∠POQ are adjacent angles )
∠NOQ - ∠NOP = ∠POQ
∠POQ = 110° - 24°
<u>∠POQ = 86°</u>
Angle POQ is 86°
Thus we can conclude option B as correct answer.
9514 1404 393
Answer:
- cable length: 300.2 ft
- anchor distance: 193.0 ft
Step-by-step explanation:
The side given is opposite the given angle. We want to find both the hypotenuse and the adjacent side in the right triangle that models the geometry.
Sin = Opposite/Hypotenuse
sin(50°) = (230 ft)/h
h = (230 ft)/sin(50°) ≈ 300.24 ft
The length of the cable must be about 300.2 feet.
__
Tan = Opposite/Adjacent
tan(50°) = (230 ft)/d
d = (230 ft)/tan(50°) ≈ 192.99 ft
The cable must be anchored about 193.0 ft from the tower.
Answer:
Option 3
Step-by-step explanation:
We want to work out the surface-area
This is a cylinder and the formula for the surface area of a cylinder is :
2πrh+2πr^2
^ means to the power of
The radius is 15
The length is 18
2(3.14)(15)(18) + 2(3.14){15}^2
Part 1:
(6.28)(15)(18)
(6.28)(270)
1695.6
Part 2:
First, we do the exponents,
15^2 = 225
(6.28)(225)
1413
Part 3:
1695.6 + 1413 = 3108.6
Answer: 3108.6
Hope this helps :)
Answer: Here I simplified it and I think its right.
Step-by-step explanation:
Cos(x) = 1 at 0 and 2pi 360 and -360 is the same angle as 2pi so all of the above if you start at 0 and make a complete circle (360) you will be back at point 0.
