2 years ago

What is the equation of the line with a slope of -2/3 through the point (-5, 2)? ◽=◽+◽

Mathematics

1 answer:

ella [17]2 years ago

8 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

$(h+k)(x)=h(x)+k(x)\\\\\bold{METHOD\ 1:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(k+h)(2)=h(2)+k(2)\\\\\text{Calculate}\ h(2)\ \text{and}\ k(2).\\\text{Put}\ x=2\ \text{to the equations of the functions}\\\\h(2)=2^2+1=4+1=5\\k(2)=2-2=0\\\\\text\\\\\text{Substitute:}\\\\(h+k)(2)=5+0=5$

$\bold{METHOD\ 2:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(h+k)(x)=h(x)+k(x)=(x^2+1)+(x-2)=x^2+x-1\\\\(h+k)(2)-\text{put}\ x=2\\\\(h+k)(2)=2^2+2-1=4+2-1=6-1=5$

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2 years ago

What is the equation of the line with a slope of -2/3 through the point (-5, 2)? ◽=◽+◽​

What is the equation of the line with a slope of -2/3 through the point (-5, 2)? ◽=◽+◽