Let us say T= probability of head turning up = 1/2 in one toss
H = probability of a tail turning up = 1/2 in one toss
Then P (56 heads or more) =
1/2^100 [ C(100,56) + C(100,57) + C(100,58) + ....
C(100,98) + C(100,99) + C(100,100) ]
where C(N, R) = N ! / [ (N - R)! R! ] number of occurrances of R formed from
N tosses.
Answer:
0.9451
Step-by-step explanation:
Remaining question? <em>"How is the result affected by the additional information that the survey subjects volunteered torespond?"</em>
Probability that at least 1 user is more careful about personal information when using a public Wi-Fi hot spot is:
P(X≥1) = 1 − P(X<1)
= 1 − P(X=0)
= 1 - [(3,0) (0.62)^0 (1-0.62)^3-0
= 1 - 0.054872
= 0.945128
= 0.9451
Thus, the probability that among three randomly selected Internet users; at least one is more careful about personal information when using a public Wi-Fi hotspot is 0.9451
Answer:
i have no more money to buy a candle shop full of dogs with cats and people
Step-by-step explanation:
ur mae
The Awnser is c obtuse angle