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2 years ago

Which correctly expresses the relationship between voltage, current, and resistance? V = I/R V = IR V = R/I V = I+R

Physics

1 answer:

Ann [662]2 years ago

8 0

Answer:

V = IR

Explanation:

Voltage is denoted by V, current is denoted by I and resistance is denoted by R. Voltage is the difference of electric potential between two points. Current is the measure of the rate of flow of electric charge. Resistance is a measure how a device reduces the current flow through itself.

The three properties are related to each other as per the Ohm's law which states that voltage and current are directly proportional to each other, it can be denoted as

Voltage (V) = Current(I) X Resistance(R).

$V = I \times R$

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Chemical phenomenon by virtue of which a body or compound is transformed by the action of an oxidant

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A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psip=75 psi. It had a wall thickness

Mekhanik [1.2K]

To solve this problem we must apply the concept related to the longitudinal effort and the effort of the hoop. The effort of the hoop is given as

$\sigma_h = \frac{Pd}{2t}$

Here,

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At the same time the longitudinal stress is given as,

$\sigma_l = \frac{Pd}{4t}$

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Then he hoop stress would be,

$\sigma_h = \frac{Pd}{2t}$

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$\sigma_l = \frac{Pd}{4t}$

$\sigma_l = \frac{75\times 8}{4\times 0.25}$

$\sigma_l = 600Psi$

The Mohr's circle is attached in a image to find the maximum shear stress, which is given as

$\tau_{max} = \frac{\sigma_h}{2}$

$\tau_{max} = \frac{1200}{2}$

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2 years ago

A block of ice at 0 degrees C, whose mass is initially 62 kg, slides along a horizontal surface, starting at a speed of 5.48 m/s

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The mass of ice melted as a result of friction between the ice and the horizontal surface is 2.78g

Explanation:

Given,

Temperature, T = 0°C

Initial mass, Mi = 62kg

Speed, s = 5.48m/s

Distance, x = 26.8m

Friction is present.

Mass of ice melted = ?

We know,

The amount of energy required for the melting of ice is exactly equal to the initial kinetic energy of the block of ice

and

$Kinetic Energy, KE = \frac{1}{2} mv^2$

Therefore, $KE = \frac{62 X 5.48 X 5.48}{2}$

KE = 930.94 Joules

Ice melting lateral heat is 334 kJ/kg = 334000 J/kg.

Therefore, the melted mass of the ice = 930.94 / 334000 = 0.00278 kg = 2.78 g.

Thus, The mass of ice melted as a result of friction between the ice and the horizontal surface is 2.78g

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