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2 years ago

Million dollar question. No joke

Mathematics

1 answer:

kotykmax [81]2 years ago

4 0

Answer:

The answer to your question is the third option

Step-by-step explanation:

If two lines are parallel, they have the same slope.

y = 1/2 x + 8

The slope of both lines is 1/2

- Find the line equation

Formula

(y - y1) = m(x - x1)

Substitution

(y - 2) = 1/2 (x +2)

Simplifying

y - 2 = 1/2x + 2/2

y - 2 = 1/2 x + 1

y = 1/2 x + 1 + 2

Result

y = 1/2 x + 3

You might be interested in

Which of the ratios below is equivalent to 5:2? Select all that apply.

Nata [24]

Answer:

Step-by-step explanation:

This is because they are both mulitplied by two so they are still equivalent

6 0

2 years ago

HELP!!!! I need help

ahrayia [7]

Answer:

1 Tenths = 10 Hundredths

10.74 - 10.60 = 0.14

0.14 = 14 hundredths

Thus, you need 10 ones, 6 tenths and 14 hundredths to make 10.74.

3 0

1 year ago

Need help with math, Lol thank you! :)

attashe74 [19]

That would be A, 22/12 and 27/12

7 0

2 years ago

Read 2 more answers

Given g ( x ) = 2 x + 3 , solve for x when g(x)=3.

padilas [110]

Answer:

x = 0

Step by step explanation:

g ( x ) = 2x + 3

If x = 0,

g ( 0 ) = 2 (0) + 3

or, g ( 0 ) = 3

<em>Hope that helped :)</em>

8 0

2 years ago

Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the

sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let $y(t)$ be the depth of water in the barrel at time $t$ , where $y$ is measured in inches and $t$ in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

$\frac{dy}{dt}=-k\sqrt{y}$

where $k$ is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by $\frac{1}{\sqrt{y}}$

$\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k$

Multiply by $dt$

$\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt$

Take integral

$\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt$

Integrate

$2\sqrt{y}=-kt+C$

Isolate $y$

$y(t)=(\frac{C}{2} -\frac{k}{2}t)^2$

We know that the water level starts at 36, this means $y(0)=36$ . We use this information to find the value of $C$ .

$36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12$

$y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2$

At t = 1, y = 34

$34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}$

So our formula for the depth of water in the barrel is

$y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\$

To find the time, $t$ , at which all the water leaks out of the barrel, we solve the equation

$\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49$

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0

3 years ago