Answer:
7
Step-by-step explanation:
I hope it helped you
We can solve with a system of equations, and use c for the amount of cans of soup and f for the amount of frozen dinners.
The first equation will represent the amount of sodium. We know the (sodium in one can times the number of cans) plus (sodium in one frozen dinner times the number of dinners) is the expression for the total sodium. We also know the total sodium is 4450, so:
250c + 550f = 4450
The second equation is to find how many of each item are purchased:
c + f = 13
Solve for c in the second equation:
c = 13 - f
Plug this in for c in the first equation:
250(13-f) + 550f = 4450
3250 - 250f + 550f = 4450
300f = 1200
f = 4
Now plug the value for f into the second equation:
c + 4 = 13
c = 9
The answer is 9 cans of soups and 4 frozen dinners.
Answer:
an=7n-19
(the last one)
Step-by-step explanation:
Answer:
3 dimes and 10 quarters
Step-by-step explanation:
If you add 7 dimes, then the number of dimes and quarters is the same, and the total increases to $3.50. A dime and a quarter have a value together of $0.35. Since there are equal numbers, the value $3.50 must be made up of some quantity of groups with a value of $0.35. That number of groups must be ...
... $3.50/$0.35 = 10
Thus, there are 10 quarters and 10-7 = 3 dimes.
_____
<em>Using an equation</em>
Let q represent the number of quarters. Then the amount Bess has is ...
... 0.10(q -7) +0.25q = 2.80
... 0.35q - 0.70 = 2.80
... 0.35q = 3.50 . . . . . add 0.70 . . . . . . . this should look familiar
... q = 3.50/0.35 = 10
