Since 16 and 25 are perfect squares you can factor the first part.
4^2-5^2(b+3)^2
=(4-5(b+3))(4+5(b+3))
=(4-5b-15)(4+5b+15)
=(-11-5b)(19+5b)
Which can be expanded if necessary,
= -209+150b-25b^2
Answer:
The distance from A to B is 736.2 to the nearest tenth foot
Step-by-step explanation:
In ΔCAB
∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A
∴ m∠CAD = m∠ACB + m∠ABC
∵ m∠ABC = 20°
∴ m∠ACB = 30° - 20° = 10°
We will use the sin rule to find the distance AB
∵
∴ ≅ 736.2 to the nearest tenth foot
Answer:
2^12
Step-by-step explanation:
answer is in photo above
I think you forgot to give the options along with the question. I am answering the question based on my research and knowledge. "<span>(-3,-4), 3,-4), (3,4)" could be the vertices of the triangle described in the question. I hope that this is the answer that you were looking for and it has come to your great help.</span>
Answer:
(D) Conclusions drawn using deductive reasoning are always valid, while conclusions drawn using inductive reasoning may or may not be valid.
Step-by-step explanation: