Answer:
(B)c = StartFraction (3) sine (45 degrees) Over sine (40 degrees) EndFraction
Step-by-step explanation:
In Triangle ABC is shown.
95 degrees
45 degrees.
|AB|=c
|BC|=3.0 cm
Using the Law of Sines
The correct option is B.
Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer: x= -2
Step-by-step explanation: use pemdas
10x + 8 = 3(x - 2) distribuite parenthesis
10x + 8 = 3x - 6
10x + 8 = 3x - 6 add like terms
7x +8= -6 add like terms
7x= -14 divide to get x alone
x= -2
Answer:
About 10.54, sorry if im wrong
Step-by-step explanation:
c= the square root of a^2+b^2