Answer:
Answer: x= -6 and y= -7
Step-by-step explanation:
Substitute 2x+5 for y in y=3x+11:
y=3x+11
2x+5=3x+11
2x+5+−3x=3x+11+−3x(Add -3x to both sides)
−x+5=11
−x+5+−5=11+−5(Add -5 to both sides)
−x=6
−x−1=6−1(Divide both sides by -1)
x=−6
Step: Substitute −6 for x in y=2x+5:
y=2x+5
y=(2)(−6)+5
y=−7(Simplify both sides of the equation)
-Source: MathPapa
Answer: the answer is x=36
Step-by-step explanation:
Simplify \frac{1}{8}(x-4)
8
1
(x−4) to \frac{x-4}{8}
8
x−4
.
-\frac{x-4}{8}=-4
−
8
x−4
=−4
2 Multiply both sides by 88.
-x+4=-4\times 8
−x+4=−4×8
3 Simplify 4\times 84×8 to 3232.
-x+4=-32
−x+4=−32
4 Regroup terms.
4-x=-32
4−x=−32
5 Subtract 44 from both sides.
-x=-32-4
−x=−32−4
6 Simplify -32-4−32−4 to -36−36.
-x=-36
−x=−36
7 Multiply both sides by -1−1.
x=36
x=36
Answer:
6 hours
Step-by-step explanation:
Set up a proportion:
15kg/5 hrs = 18kg/x hrs
Cross multiply:
5(18)=15x
90 = 15x
Divide by 15:
90/15 = x
6 = x
-5.1=1.3+w/4
Subtract 1.3 from both sides
-6.4=w/4
Multiply both sides by 4
-25.6=w
Check work:
-5.1=1.3+(-25.6/4)
-5.1=1.3+(-6.4)
-5.1=1.3-6.4
-5.1=-5.1
Hope this helps! :)
Answer:
The rocket hits the gorund after approximately 10.71 seconds.
Step-by-step explanation:
The height of the rocket <em>y</em> in feet <em>x</em> seconds after launch is given by the equation:
And we want to find the time in which the rocket will hit the ground.
When it hits the ground, its height above ground will be 0. Hence, we can let <em>y</em> = 0 and solve for <em>x: </em>
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We can use the quadratic formula:
In this case, <em>a</em> = -16, <em>b</em> = 165, and <em>c </em>= 69.
Substitute:
Evaluate:
Hence, our solutions are:
Since time cannot be negative, we can ignore the first answer.
So, the rocket hits the gorund after approximately 10.71 seconds.