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Answer: Choice A. (7,4)</h3>
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Explanation:
Use the slope and given point to find the y intercept
y = mx+b
8 = (-2/3)*(1) + b
8 = -2/3 + b
8 + 2/3 = b
24/3 + 2/3 = b
26/3 = b
b = 26/3
The equation of the line is y = (-2/3)x + 26/3
To confirm this, plug in x = 1 and we should get y = 8, due to the point (1,8)
y = (-2/3)x + 26/3
y = (-2/3)*1 + 26/3
y = -2/3 + 26/3
y = (-2+26)/3
y = 24/3
y = 8
So that verifies we have the correct equation.
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Next, go through each answer choice to see if the x coordinate of the point leads to the y coordinate.
If we try x = 7, then,
y = (-2/3)x + 26/3
y = (-2/3)(7) + 26/3
y = -14/3 + 26/3
y = (-14+26)/3
y = 12/3
y = 4
This shows that (7,4) is on the line. Choice A is the answer
That rules out choice B.
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If we tried x = -5, then,
y = (-2/3)x + 26/3
y = (-2/3)(-5) + 26/3
y = 10/3 + 26/3
y = 36/3
y = 12
meaning that (-5,12) is on the line. That rules out choices C and D.
Refer to the graph below. It visually confirms that of the four answer choices, only point A is on the line. I used GeoGebra to make the graph.
Answer:
y = 3/4x+7
Step-by-step explanation:
The slope is 3/4 and a point is (-8,1)
We can use point slope to make an equation for the line
y-y1 = m(x-x1)
y-1 = 3/4(x--8)
y-1 = 3/4(x+8)
y-1 = 3/4x +6
Add 1 to each side
y-1+1 = 3/4 x+6+1
y = 3/4x+7
This is in slope intercept form (y=mx+b)
Not sure but i think its 60 i hope its right
Answer:
g(x)=log(x+4)
Step-by-step explanation:
Here the parent function is f(x)=log x. The function has y intercept as 0 at x=1 .
If we observe the translated function we will observe that , the y intercept of new function is 0 at x=-3. Hence the function is moving ahead of the parent function by 4 units and reaches the y intercept being 0.
If we graph
g(X)= log X
the y intercept will be at (1,0)
X = 1 , Y =0
at X=1 , x = -3 or x = X-4
or X=x+4
Hence
new function will be g(x)=log ( x+4)
Answer:
Step-by-step explanation:
We are given the following information in the question:
where a > 0 and b > 0.
where v(t) is the required tumor volume as a function of time that has an initial tumor volume of V(0) = 1 cubic mm.