Answer:
Torque=13798.4 N.m
Explanation:
Given data
Mass of beam m₁=500 kg
Mass of the person m₂=70 kg
length of steel r₁=4.40m
center of gravity of the beam is at r₂=r₁/2 =4.40/2 = 2.20m
To find
Torque
Solution
Torque due to beam own weight
Torque due to person
Now for total torque
Q1. The answer is 8.788 m/s
V2 = V1 + at
V1 - the initial velocity
V2 - the final velocity
a - the acceleration
t - the time
We have:
V1 = 4.7 m/s
a = 0.73 m/s²
t = 5.6 s
V2 = ?
V2 = 4.7 + 0.73 * 5.6
V2 = 4.7 + 4.088
V2 = 8.788 m/s
Q2. The answer is 9.22 s
V2 = V1 + at
V1 - the initial velocity
V2 - the final velocity
a - the acceleration
t - the time
We have:
V2 = 0 (because it reaches a complete stop)
V1 = 4.7 m/s
a = -0.51 m/s²
t = ?
0 = 4.7 + (-0.51)*t
0 = 4.7 - 0.51t
0.51t = 4.7
t = 4.7 / 0.51
t = 9.22 s
Answer:
it would be letter E. near oceanic ridges
Explanation:
new ocean crust is formed at the mid ocean ridges
<span>First, water evaporates from the ocean to the atmosphere, then... put each step in the correct order.
</span>Second- atmospheric circulation advects the water.
Third- water condensates to form clouds.
Fourth- precipitation falls from clouds to the land.
Fifth- some water stored as snow or ice.
Sixth- water either ±ows along the surface in rivers and lakes or infiltrates the ground.
Seventh- water returns to the ocean.
Answer:
The answer is "".
Explanation:
Its minimum velocity energy is provided whenever the satellite(charge 4 q) becomes 15 m far below the square center generated by the electrode (charge q).
It's ultimate energy capacity whenever the satellite is now in the middle of the electric squares:
Potential energy shifts:
Now that's the energy necessary to lift a satellite of 100 kg to 300 km across the surface of the earth.
This satellite is transmitted by it system at a height of 300 km and not in orbit, any other mechanism is required to bring the satellite into space.