The first two pairs.. just substitute the x-coordinate and find y
Answer:
A) x = 10-/3, y = 20
Step-by-step explanation:
Log w (x^2-6)^4
Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4
Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 = log w + 4 log (x^2-6)
Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
Mean, x_bar = 1518
Standard deviation, sigma = 325
Range required: 1550 ≤ X ≤ 1575
Z = (X - x_bar)/sigma
Z1 = (1550-1518)/325 ≈ 0.1
Z2 = (1575-1518)/325 ≈ 0.18
From Z tables,
P(Z1) = 0.5398
P(Z2) = 0.5714
P(1550≤X≤1575) = P(Z2) - P(Z1) = 0.5714 - 0.5398 = 0.0316
The correct answer is C.
Answer:
3
Step-by-step explanation:
To simplify this expression, we will simply work with the numerator, then the denominator, and then the fraction as a whole, following PEMDAS.
Numerator: 12 - 6 + 5 * (-3)^2
= 12 - 6 + 5 * (9)
= 12 - 6 + 45
= 6 + 45
= 51
Denominator: 17
So our simplified fraction is as follows:
51/17
Which can be reduced to the whole number, 3.
Cheers.