Answer:
The correct option is;
r = √(x² + y²)
θ = tan⁻¹(y/x)
Step-by-step explanation:
The rectangular coordinate of a complex number on the complex plane is given as (x, y)
Given that the complex number is represented by a point on the plane, we have;
The distance, r, of the point from the origin, (0, 0) is r = √(x² + y²)
The direction, θ, by which we rotate to be in line with the point on the complex number is given by tan⁻¹(y/x)
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Answer with explanation:</h2>
The function represents the area of a circle(A) is given by :-
To determine the area of a circle whose radius is 11 inches. , we put the value of r=11 inches, we get
Now, we put 
in the above function , we get
Any line can be expresses as:
y=mx+b where m=slope=(y2-y1)/(x2-x1) and b=y-intercept (value of y when x=0)
First find the slope:
m=(2-0)/(8-0)=2/8=1/4 so we have thus far:
y=0.25x+b, we solve for b using any point on the line, (8,2)
2=0.25(8)+b
2=2+b
0=b
So the line is:
y=.25x which they might also express as y=x/4
The answer is E. (1/4)x
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
