Set s(t) = 0 which means it hits the ground. The formula doesn't fit the parameters given as it shows that the pitcher is standing on something 37 feet high.
<span>s(t)=-16t^2+140t+37 and has an initial velocity of 140.
Graphing or solving this, t= 9 seconds when it hits the ground.
The velocity V(t) is the derivative of s(t)
V(t) = -32t+140
V(9) = -148 ft/second which is going down
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Just set it equal to zero and solve using the quadratic equation.
Answer:
x and 2x+1
Step-by-step explanation:
The answer is the last option (Option D), which is:
D. 25
The explanation is shown below:
1. You have that:
(a ± b)^2=a^2 <span>± 2ab + b^2
2. The expression given in the problem is:
</span><span>x^2-10x+n
Where x^2=a and 2ab=10x
2b=10
b=10/2
b=5
3. Therefore, you have:
b^2=5
b^2=25
b^2=n
n=25</span>
