The figure (i) have a distance of 15.996 meters and a displacement of 13.892 meters and (ii) a distance of 480 centimeters and a displacement of 339.411 centimeters
<h3>How to find the distance and displacement in each trajectory</h3>
The distance is the sum of the lengths that form a trajectory and the displacement is the distance between the <em>initial</em> and <em>final</em> point of a trajectory. Then, we have the following results for each case:
Case I
Distance
d = 5 m + 0.5π · (7 m)
d ≈ 15.996 m
Displacement
D ≈ 13.892 m
Case II
Distance
d = 8 · (60 cm)
d = 480 cm
Displacement
D ≈ 339.411 cm
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Answer:
(t + 6)(t - 6)
Step-by-step explanation:
(t - 6)(t + 6)
(t . t) + (t . (6) + ((-6) . t) + ((-6) . 6)
= t² - 6t + 6t - 36
= t² - 36
so,
t² - 36 = (t + 6)(t - 6)
X-intercept: (3.5,0)
Y-intercept: (2.5,0)
Answer: x = 132 daw
Step-by-step explanation: believe me