I hope this helps you understand how to do the problem.
If $200 is the maximum a coach can spend on new shorts, and needs at least 15 shorts, then you could divide or use an inequality. first take the maximum number (200) and the minimum amount (15s) and use the minimum and maximum signs of knowledge to form an inequality. you should end up with 15s<200.
Hey there, Dudedan!
In a#b = a+2b, we have the first term, a, plus 2 times the second term, b.
Let's try that with 3#4.
3#4 = 3+2(4) =
3 + 8 = 11.
Hope this helps!
46
When it says f(4) that means x=4
So you then just fill in all the x’s with 4’s and solve as normal