You are given a set of data with a mean of 50 and standard deviation of 8. Using the normal curve, give an example of an outlier
1 answer:
Answer:
<u>Anything less than 26, and greater than 74.</u>
Step-by-step explanation:
In normal distribution, the outlier is more than e ≈ 2.72 standard deviations above quartile 3, and e standard deviations below quartile 1. These quartiles are divisions that make up what is known as the innerquartile range(IQR). Which defines the variability of a data set given by IQR = Q3-Q1.
Given that the mean of this data is 50, and the standard deviation is 8.
Our outliers are anything less than 26, and anything greater than 74. Since outliers are anything outside the mean plus and minus the standard deviation times 3
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The common difference is the difference between successive terms, therefore
d = a₃ - a₂ = a₄ - a₃, and so on..
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For the arithmetic sequence
1,3,5, ...,
the common difference is d= 3 - 1 = 2.
The n-th term is
For example, the 10-term is
a₁₀ = 1 + (10-1)*2 = 19
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a₁, a₂, ...,
Because the given sequence is an arithmetic progression (AP), the equation satisfied is
where
d = the common difference.
The common difference may be determined as
d = a₂ - a₁
The common difference is the difference between successive terms, therefore
d = a₃ - a₂ = a₄ - a₃, and so on..
The sum of the first n terms is
Example:
For the arithmetic sequence
1,3,5, ...,
the common difference is d= 3 - 1 = 2.
The n-th term is
For example, the 10-term is
a₁₀ = 1 + (10-1)*2 = 19
Th sum of th first 10 terms is
S₁₀ = (10/2)*(1 + 19) = 100