Alcohol risk that one is hard to answer sorry if i wasn't much help
Answer:
λ = 864 nm
Explanation:
To find the wavelength of the light you use the following formula, which determines the position of the m-th fringe in an interference pattern:
(1)
ym: position of a bright fringe
D: distance from the slits to the screen = 3,7 m
d: distance between slits = 0,2mm = 0,2 *10^-3 m
m: order of the fringe
λ: wavelength of the light
You have the distance from the central peak to the third fringe (0,048m). Then, you can use the equation (1) with m=3 and solve for the wavelength:
henc, the wavelength of the light is 864nm
Answer:
Average :
UCL = 4.15
LCL = 2.65
Range :
UCL = 2.75
LCL = 0
Explanation:
Given :
Sample size, n = 5
Average, X = 3.4
Range, R = 1.3
A2 for n = 5 ; equals 0.577 ( X chart table)
For the average :
Upper Control Limit (UCL) :
X + A2*R
3.4 + 0.577(1.3) = 4.1501
Lower Control Limit (LCL) :
X - A2*R
3.4 - 0.577(1.3) = 2.6499
FOR the range :
Upper Control Limit (UCL) :
UCL = D4*R
D4 for n = 5 ; equals = 2.114
UCL = 2.114*1.3 = 2.7482
Lower Control Limit (LCL) :
LCL = D3*R
D3 for n = 5 ; equals = 0
LCL = 0 * 1.3 = 0
1000 khz am radio station broadcasts with a power of 20 kw number of photon emitted per second is 30.16 x 10^30 photon/s.
The frequency of the radio station is:
f
=
1000
k
H
z
=
1
×
10^6Hz
The transmit power is: P = 20kW = 20 X 10^3 W
The transmit power is: h = 6.63 x 10 ^-34 m^2.kg/s
The number of photon emitted per second = N = P/hf = <u>30.16 x 10^30 </u>photon/s.
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