Ecell = E°cell - RT/vF * lnQ
R is the gas constant: 8.3145 J/Kmol
T is the temperature in kelvin: 273.15K = 0°C, 25°C = 298.15K
v is the amount of electrons, which in your example seems to be six (I'm not totally sure)
F is the Faradays constant: 96485 J/Vmol (not sure about the mol)
Q is the concentration of products divided by the concentration of reactants, in which we ignore pure solids and liquids: [Mg2+]³ / [Fe3+]²
Standard conditions is 1 mol, at 298.15K and 1 atm
To find E°cell, you have to look up the reduction potensials of Fe3+ and Mg2+, and solve like this:
E°cell = cathode - anode
Cathode is where the reduction happens, so that would be the element that recieves electrons. Anode is where the oxidation happens, so that would be the element that donates electrons. In your example Fe3+ recieves electrons, and should be considered as cathode in the equation above.
When you have found E°cell, you can just solve with the numbers I gave you.
I think it is D the last choice
Answer:
Properties of Alkaline Earth Metals
shiny.
silvery-white.
somewhat reactive metals at standard temperature and pressure.
readily lose their two outermost electrons to form cations with a 2+ charge.
low densities.
low melting points.
low boiling points.
Explanation:
Answer:200/3 M which is approximately equal to 66.6667 M
Explanation:Molarity is defined as the number of moles of solute per liter of solution.
It can be calculated as follows:
We are given that:
number of moles of solute = 8 moles
volume of solution = 120 ml = 0.12 liters
Substitute with the givens in the above equation to get the molarity as follows:
molarity =
Hope this helps :)
Answer:
3.01 × 10^24 atoms of vitamin D
Explanation:
The number of atoms, molecules or ions present in a substance is given by the Avogadro's number which is 6.02 × 10^23.
Hence;
1 molecule of vitamin D contains 6.02 ×10^23 atoms
5 molecules of vitamin D contains 5 × 6.02 ×10^23/1
= 3.01 × 10^24 atoms of vitamin D