Answer: D
Step-by-step explanation:
Consider the first equation. Subtract 3x from both sides.
y−3x=−2
Consider the second equation. Subtract x from both sides.
y−2−x=0
Add 2 to both sides. Anything plus zero gives itself.
y−x=2
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
y−3x=−2,y−x=2
Choose one of the equations and solve it for y by isolating y on the left hand side of the equal sign.
y−3x=−2
Add 3x to both sides of the equation.
y=3x−2
Substitute 3x−2 for y in the other equation, y−x=2.
3x−2−x=2
Add 3x to −x.
2x−2=2
Add 2 to both sides of the equation.
2x=4
Divide both sides by 2.
x=2
Substitute 2 for x in y=3x−2. Because the resulting equation contains only one variable, you can solve for y directly.
y=3×2−2
Multiply 3 times 2.
y=6−2
Add −2 to 6.
y=4
The system is now solved.
y=4,x=2
26% of 50
26/100 * 50
13
50 - 13 = 37
Answer:
Step-by-step explanation:
1) (x-3),(x-8)
2) 3x^3+3x^2=27x
3
(
x
3^3+
x
^2
−
9
x
−
9
)
3
(
x
^2
(
x
+
1
)
−
9
(
x
+
1
)
)
3
(
(
x
+
1)(
x
^2
−
9
)
)
3
(
(
x
+
1
)
(
x
^2
−
3
^2
)
)
3
(
x
+
1
)
(
x
+
3
)
(
x
−
3
)
Answer:
C
Step-by-step explanation:
Answer:
x=-2
Step-by-step explanation:
x^2+4x+4 = 0
(x+2)(x+2) = 0
x+2=0
x=-2
