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2 years ago

The triangle is: scalene and obtuse. isosceles and acute. equilateral and acute. None of these choices are correct.

Mathematics

1 answer:

USPshnik [31]2 years ago

5 0

Answer:

Isosceles and acute

Step-by-step explanation:

=> This triangle have two sides congruent so it's isosceles.

=> This triangle has all of it's angles less than 90 so it is an acute triangle.

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What is the radical equivalent for 197^7/8?

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Answer:

$\sqrt[8]{197^{7} }$

Step-by-step explanation:

$\sqrt[8]{197^{7} }$

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2 years ago

Which type of energy transformation occurs in photosynthesis?

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Answer:

Light to chemical

Step-by-step explanation:

Photosynthesis is a transformation of light to chemical energy because energy from the sun is absorbed and then made into glucose for the plant.

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Barry Katz earns $1,275 per week. He is married and claims two exemptions. What is Barry’s income tax? Use percentage method.

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Answer: I’m not sure but I think the answer is $255

Step-by-step explanation:

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2 years ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

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3 years ago

Find the value of n in the equation 6.2n – 3.7n = 85 + 45.

Hoochie [10]

Answer:

D. 52

Step-by-step explanation:

Add 85 and 45 to get 130.

6.2n-3.7n=130

Subtract 3.7 from 6.2

2.5n=130

divide 130 by 2.5 to find n

N=52

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2 years ago

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