PLEASE HELP NOW --- >N is a 2-digit even number. If the last two digits of N^2 is the same as N, what is the sum of digits of
1 answer:
Answer:
76.
Step-by-step explanation:
It is given that N is a 2-digit number.
Last two digits of N^2 is the same as N.
We know that, a number is even if it ends with 0,2,4,6,8.
If 0 is in end then we get two zeros in the square of that number.
It is clear that, number should ends with 6 to get the same number at the end.
It is clear that last two digits of (76)^2 is the same as 76.
Therefore, the required number is 76.
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Answer:
ind the absolute value vertex. In this case, the vertex for y=−|x|−2 is (0,−2).
(0,−2)
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Interval Notation:
(−∞,∞)
Set-Builder Notation: {x|x ∈ R}
For each x value, there is one y value. Select few x values from the domain. It would be more useful to select the values so that they are around the x value of the absolute value vertex.
x y
−2 −4
−1 −3
0 −2
1 −3
2 −4
Step-by-step explanation:
