Methane is a hydrocarbon which when burns in air (combustion) produces carbon dioxide and water. The equation for the reaction;
CH4 +2O2 = CO2 +2H2O
When one mole of methane combusts 2 moles of water are formed
Therefore; when 22 moles of methane combusts 44 moles of water are formed (22 ×2)
Answer:
100%
Explanation:
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Answer:
If there is 0.66 moles of iron(III)oxide produced, there reacte 0.99 moles of oxygen (O2)
Explanation:
Step 1: Data given
Number of moles iron (III) oxide (Fe2O3) = 0.66 moles
Step 2: The balanced equation
4Fe + 3O2 → 2Fe2O3
Step 3: Calculate moles of oxygen (O2)
For 4 moles Fe consumed, we need 3 moles of O2 to produce 2 moles of Fe2O3
For 0.66 moles Fe2O3 produced, we need 3/2 * 0.66 = 0.99 moles of O2
If there is 0.66 moles of iron(III)oxide produced, there reacte 0.99 moles of oxygen (O2)
