Answer:
Explanation: according to Coulomb's inverse-square law is proportional to the square of distance between them and is given by
where r is the distance between the charges & k is the Coulomb's constant
k=1/(4*ε_0*π)
k=9*10^9
the distance between the charges in this question is d_1
hence the magnitude of the force exerted by q_0 on q_1 is given by
due to location of particle 1 above the particle 0 the direction of force is parallel to y axis and in vector form
Answer:
-10 m/s²
Explanation:
a = Δv / Δt
a = (20 m/s − 50 m/s) / 3 s
a = -10 m/s²
The car is moving faster/accelerating quicker
Answer:
after 6 second it will stop
he travel 36 m to stop
Explanation:
given data
speed = 12 m/s
distance = 100 m
decelerates rate = 2.00 m/s²
so acceleration a = - 2.00 m/s²
to find out
how long does it take to stop and how far does he travel
solution
we will apply here first equation of motion that is
v = u + at ......1
here u is speed 12 and v is 0 because we stop finally
put here all value in equation 1
0 = 12 + (-2) t
t = 6 s
so after 6 second it will stop
and
for distance we apply equation of motion
v²-u² = 2×a×s ..........2
here v is 0 u is 12 and a is -2 and find distance s
put all value in equation 2
0-12² = 2×(-2)×s
s = 36 m
so he travel 36 m to stop
Answer: 3. F1 = F2
Explanation:
According to <u>Newton's law of Gravitation</u>, the force exerted <u>between two bodies</u> or objects of masses and and separated by a distance is equal to the product of their masses divided by the square of the distance:
(1)
Where is the gravitational constant
Now, in the especific case of the Earth and the satellite, where the Earth has a mass and satellite a mass , being both separated a distance , the force exerted by the Earth on the satellite is:
(2)
And the force exerted by the satellite on the Earth is:
(3)
As we can see equations (2) and (3) are equal, hence the magnitude of the gravitational force is the same for both: