The zeroes of <span>f(x) = x^5-12x^2+32x can be found by factoring,
</span><span>f(x) = x^5-12x^2+32x=(x-8)(x-4)
By the zero product theorem, (x-8)=0 or (x-4)=0 which means
x=8 or x=4.
So the zeroes of f(x) are S={4,8}</span>
All you have to do is subtract 3/8 from 7 which would give you 9 and 1/3
Answer:
14 and 2/3rd cups of flour for 4 batches
Step-by-step explanation:
C is on the line and D is not on the line.
-1/2(-40)+1=21
-1/2(20)+1≠-11
G(x)=x^2-10x+16
g(x)=x^2-10x+25-25+16
g(x)= (x-5)^2-9
minimum value is -9