1000 your welcome no problem
What kind of question is that? That’s a statement.
√z = 13 - 8
√z = 5
z = 5²
z = 25
In this case the z can be any number, however z cannot be less than 0 and that is the restriction. (for example; √-1 = irrational number, cannot be solved.)
Answer:
B. 6i√6
General Formulas and Concepts:
<u>Algebra II</u>
- Imaginary Numbers: √-1 = i
Step-by-step explanation:
<u>Step 1: Define expression</u>
√-216
<u>Step 2: Simplify</u>
- Factor: √-1 · √216
- Simplify: i · 6√6
- Multiply: 6i√6
Answer:
B
Step-by-step explanation:
