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2 years ago

Please Please Please Can Help Me On This Question!!!!! I Give Thanks!!!!

Physics

1 answer:

Kaylis [27]2 years ago

5 0

I'm doing questions in grade 10 math working on imperial system how should I give my answers in decimals or fraction it's an adult learning experience

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How does surfing relate to physics

uranmaximum [27]

It’s physical something you can physically do

5 0

2 years ago

Delivery trucks that operate by making use of energy stored in a rotating flywheel have been used in Europe. The trucks are char

Marta_Voda [28]

Answer:

KE = 2.535 x 10⁷ Joules

Explanation:

given,

angular speed of the fly wheel = 940 rad/s

mass of the cylinder = 630 Kg

radius = 1.35 m

KE of flywheel = ?

moment of inertia of the cylinder

$I = \dfrac{1}{2}mr^2$

= $\dfrac{1}{2}\times 630\times 1.35^2$

= 574 kg m²

kinetic energy of the fly wheel

$KE = \dfrac{1}{2}I\omega^2$

$KE =\dfrac{1}{2}\times 574\times 940^2$

KE = 2.535 x 10⁷ Joules

the kinetic energy of the flywheel is equal to KE = 2.535 x 10⁷ Joules

5 0

2 years ago

In a series RLC ac circuit, a second resistor is connected in series with the resistor previously in the circuit. As a result of

AnnyKZ [126]

Answer:

* The first thing we observe is that the frequency response does not change

* The current that circulates in the circuit decreases due to the new resistance at the resonance point,

Z = R + R₂

Explanation:

The impedance of a series circuit is

Z₀² = R² + (X_L-X_C) ²

when we place another resistor in series the initial resistance impedance changes to

Z² = (R + R₂) ² + (X_L - X_C) ²

let's analyze this expression

* The first thing we observe is that the frequency response does not change

* The current that circulates in the circuit decreases due to the new resistance at the resonance point,

Z = R + R₂

8 0

2 years ago

The answer please? I have exam tomo

makkiz [27]

Please be determined and being hardworking person do not rely on the other people to make your problems solved

Explanation:

Ok?

5 0

2 years ago

A Mercedes-Benz 300SL (m = 1700 kg) is parked on a road that rises 15 degrees above the horizontal. What are the magnitudes of (

kogti [31]

Answer: See below

Explanation:

Given:

Mass of the Mercedes-Benz (m) = 1700 kg

Inclination of the road (θ) = 15.0

The free body diagram is shown in figure attached below

a) The normal force is equal to the cos component of the weight of the car.

$\begin{aligned}&f=m g \cos \theta \\&f=1700 \times 9.81 \times \cos 15 \\&f=16108.74 \mathrm{~N}\end{aligned}$

b) The static force will be equal to the weight's sin component.

$\begin{aligned}&f=m g \sin \theta \\&f=1700 \times 9.81 \times \sin 15 \\&f=4316.32 \mathrm{~N}\end{aligned}$

4 0

1 year ago