A person is trying to lift a crate that has a mass of 30 kg. The normal force of the floor is currently supplying 150 N of force
2 answers:
Answer:
The exerting force by the person is 294 N.
(3) is correct option.
Explanation:
Given that,
Mass of crate = 30 kg
Normal force = 150 N
When a person is lifting a crate then the crate does not contact the floor
So, the normal force is zero.
We need to calculate the exerting force by the person
Using formula of force
Hence, The exerting force by the person is 294 N.
You might be interested in
Hi there! Lets see!
- m is mass, and its units are kg
- k is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²
Therefore:
The period is given in seconds so the formula is dimensionally correct.
Answer:
w = 3.2 rev / min
Explanation:
For this exercise we will use the centrine acceleration equal to the acceleration of gravity
a = v² / r
Angular and linear variables are related.
v = w r
Let's replace
a = w² r = g
w = √ g / r
r = d / 2
r = 175/2 = 87.5 m
w = √( 9.8 / 87.5)
w = 0.3347 rad / s
Let's reduce to rotations per min
w = 0.3347 rad / s (1 rov / 2pi rad) (60 s / 1 min)
w = 3.2 rev / min
Suppose the space station rotates counterclockwise, we have two possibilities for the car
The first car turns counterclockwise (same direction of the station
=
r
[texwv_{c}[/tex] = / r
[texwv_{c}[/tex] = 25.0 / 87.5
[texwv_{c}[/tex] = 0.286 rad / s
When the two rotate in the same direction their angular speeds are subtracted
w total = w -[texwv_{c}[/tex]
w total = 0.3347 - 0.286
w total= 0.487 rad / s
The car goes in the opposite direction of the station the speeds add up
w = 0.3347 + 0.286
w = 0.62 rad / s
From this values we can see that the person feels a variation of the acceleration of gravity, feels that he has less weight when he goes in the same direction of the season and that his weight increases when he goes in the opposite direction to the season.