<em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Nope you posted this five days ago no need for another answer.
Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
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x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
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<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)
Answer:
125 p^3 g^3
Step-by-step explanation:
(5pg)^3
We know that (ab)^c = a^c * b^c
5^3 p^3 g^3
125 p^3 g^3
Answer:
B.
Step-by-step explanation:
Here the best method to solve is by substituting the end values of the set in each option , otherwise it will a time consuming problem.
Now substitute x=-4 in all the options
A.
16+8-8=16>0
so out of option A and C option C is correct.
B.
16-8-8=0 which means for the values of x>-4 is less than 0
Now substitute x=2 in all the options
A.
4-4-8=-8<0 . so option A and C both are incorrect.
B.
4+4-8=0 which means for the values of x<2 is less than 0
Therefore the correct option is B