2 years ago

(3b-5)^2-c^2 how do I factor this using grouping?

Mathematics

1 answer:

klemol [59]2 years ago

3 0

So you see it is the difference of 2 perfect squares
a^2-b^2=(a+b)(a-b)
so
(3b-5)^2-c^2=(3b-5+c)(3b-5-c)

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