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2 years ago

10 skeins of yarn will make for scars how many scarves can be made with 25 skeins of yarn

Mathematics

1 answer:

zhannawk [14.2K]2 years ago

4 0

Answer:

Step-by-step explanation:

Ten divided by four is 2.5 so you can make obe a rave with 2.5 skeins 2.5*10=25 so you can make ten scarves

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The sum of two consecutive interferes is 515 write an equation that models this situation and find the values of the two integer

o-na [289]

x + x + 1 = 515

2x + 1 = 515

2x = 514

x = 257 <====== One of the answer

257 + 1 =258 <====== the other answer

3 0

2 years ago

NEED HELP PLEASEE!!! I START SCHOOL TOMORROW

erastovalidia [21]

27. 110.5%
28. I can’t figure out.
29. 20%

3 0

2 years ago

Read 2 more answers

Find the perimeter of a field that has length 2/x + 1 and width 5/x^2 -1.

Semmy [17]

Answer:

D)4x + 6/(x + 1)(x - 1)

Step-by-step explanation:

A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle

$p=2(l+w)$

where

$p$ is the perimeter

$l$ is the length

$w$ is the width

We know from our problem that the field has length 2/x + 1 and width 5/x^2 -1, so $l=\frac{2}{x+1}$ and $w=\frac{5}{x^2-1}$ .

Replacing values:

$p=2(l+w)$

$p=2(\frac{2}{x+1} +\frac{5}{x^2-1})$

Notice that the denominator of the second fraction is a difference of squares, so we can factor it using the formula $a^2-b^2=(a+b)(a-b)$ where $a$ is the first term and $b$ is the second term. We can infer that $a=x^2$ and $b=1^2$ . So, $x^2-1=(x+1)(x-1)$ . Replacing that:

$p=2(\frac{2}{x+1} +\frac{5}{x^2-1})$

$p=2(\frac{2}{x+1} +\frac{5}{(x+1)(x-1})$

We can see that the common denominator of our fractions is $(x+1)(x-1)$ . Now we can simplify our fraction using the common denominator:

$p=2(\frac{2(x-1)+5}{(x+1)(x-1)} )$

$p=2(\frac{2x-2+5}{(x+1)(x-1)} )$

$p=2(\frac{2x+3}{(x+1)(x-1)} )$

$p=\frac{4x+6}{(x+1)(x-1)}$

We can conclude that the perimeter of the field is D)4x + 6/(x + 1)(x - 1).

3 0

2 years ago

14. A company uses many different delivery

ziro4ka [17]

Answer:

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Sent by ABC Speedy Delivery Service.

Event B: Arrived on time.

The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.

This means that $P(A) = 0.71$

The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.

This means that $P(B|A) = 0.93$

Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)*P(A) = 0.93*0.71 = 0.6603$

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

8 0

2 years ago

Which expression is equivalent to b^-2/ab^-5?<br>a) a/b^5<br>b)1/ab^5<br>c)a^3b/1<br>d)b/a

Snezhnost [94]

$\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{-n}}\implies a^{{ n}}\\\\
-------------------------------\\\\
\cfrac{b^{-2}}{ab^{-5}}\implies \cfrac{b^{-2}\cdot b^{+5}}{a}\implies \cfrac{b^{-2+5}}{a}\implies \cfrac{b^3}{a}$

4 0

2 years ago