If h + 12 =22, then h= 10. name the property

Which iequailty model and solution set best represents the possible side lengths of miriam's bulletin board?

faltersainse [42]

Question:

Miriam is making a bulletin board that is shaped like a square. She has 72 inches of border material. If x represents the length of one side of the bulletin board, which inequality model and solution set best represents the possible side lengths of Miriam's bulletin board?

Answer:

$x \le 18$

Step-by-step explanation:

Given

$Border\ Material = 72$

Required

Determine an inequality for x

Represent the side lengths of the border with y. So:

Since the border is on the 4 sides, then

$4y = 72$ -- i.e. the perimeter of the border material

Solve for y

$y =\frac{72}{4}$

$y =18$

Recall that x represents the board's side length.

Since x will be situated inside the boarder, then.

$x \le y$

Substitute $y =18$

$x \le 18$

6 0

2 years ago

Help please this is due tomorrow, and i still have a lot more to do, will give brainliest

____ [38]

Answer:

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Step-by-step explanation:

fdfdhfhgthngf

7 0

2 years ago

Please help me ASAP!!!

vlada-n [284]

Answer:

a) 6 1/4% of $3,875 is $242.18.

b) 16 2/3% of 96 lamps is 16 lamps.

c) 87 1/2% of 540.72 is 473.11

d) 33 1/3% of 750 boys is 252.52 boys

e) 66 1/2 % of 240 kg is 159.6 kg.

Step-by-step explanation:

x% of y is calculated as $\frac{x}{ 100} \times y$

Here calculating the given percentages:

a) 6 1/4% of $3,875

Now, 6 1/4 = 6+ 1/4 = 6.25

⇒6.25% of $3,875 = $\frac{6.25}{100} \times 3,875 = 242.18$

Hence, 6 1/4% of $3,875 is $242.18.

b) 16 2/3% of 96 lamps

Now, 16 2/3 = 16+ 2/3 = 16.67

⇒16.67% of 96 lamps = $\frac{16.67}{100} \times 96 = 16$

Hence, 16 2/3% of 96 lamps is 16 lamps.

c) 87 1/2% of 540.72

Now, 87 1/2 = 87+ 1/2 = 87.5

⇒87.5 % of 540.72 = $\frac{87.5}{100} \times 540.72 = 473.11$

Hence, 87 1/2% of 540.72 is 473.11

d) 33 1/3% of 750 boys

Now, 33 1/3 = 33+ 1/3 = 33.67

⇒33.67 % of 750 boys = $\frac{33.67}{100} \times 750 = 252.52$

Hence, 33 1/3% of 750 boys is 252.52 boys

e) 66 1/2 % of 240 kg

Now, 66 1/2 = 66+ 1/2 = 66.50

⇒66 1/2 % of 240 kg = $\frac{66.50}{100} \times 240 kg = 159.6$

Hence, 66 1/2 % of 240 kg is 159.6 kg.

4 0

2 years ago

What is the smallest integer k>2000 such that both 17k/66 and 13k/105} are terminating decimals?

Dvinal [7]

17k/66 and 13k/105 must reduce to fractions with a denominator that only consists of powers of 2 or 5.

For example, some fractions with terminating decimals are

1/2 = 0.5

1/4 = 1/2² = 0.25

1/5 = 0.2

1/8 = 1/2³ = 0.125

1/10 = 1/(2•5) = 0.1

1/16 = 1/2⁴ = 0.0625

and so on, while some fractions with non-terminating decimals have denominators that include factors other than 2 or 5, like

1/3 = 0.333…

1/6 = 1/(2•3) = 0.1666…

1/7 = 0.142857…

1/9 = 1/3² = 0.111…

1/11 = 0.09…

1/12 = 1/(2²•3) = 0.8333…

etc.

Since 66 = 2•3•11, we need 17k to have a factorization that eliminates both 3 and 11.

Similarly, since 105 = 3•5•7, we need 13k to eliminate the factors of 3 and 7.

In other words, 17k must be divisible by both 3 and 11, and 13k must be divisible by both 3 and 7. But 13 and 17 are both prime, so it's just k that must be divisible by 3, 7, and 11. These three numbers are relatively prime, so the least positive k that meets the conditions is LCM(2, 7, 11) = 231, and thus k can be any multiple of 231.

If you're familiar with modular arithmetic, this is the same as solving for k such that

13k ≡ 0 (mod 3)

17k ≡ 0 (mod 3)

17k ≡ 0 (mod 7)

13k ≡ 0 (mod 11)

and the Chinese remainder theorem says that k = 231n solves the system of congruences, where n is any integer.

Now it's just a matter of finding the smallest multiple of 231 that's larger than 2000, which easily done by observing

2000 = 8•231 + 152

and so k = 9•231 = 2079.

3 0

1 year ago

One family spends $134 on 2 adult tickets and 3 youth tickets at an amusement park. Another family spends $146 on 3 adult ticket

AnnZ [28]

3x + 2y = $134
2x + 3y = $146

Using elimination to solve for x

9x +6y = 3*134 Multiplying 1st equation by 3

-4x -6y = -2*146 | Multiplying 2nd equation by -2

5x = 3*134 - 2*146

5x = $110

x = $22, the cost of the youth ticket

Put x= 22 Into An Equation Then Solve For y

3(22)+2y= 134
66+ 2y=134
Subtract 66
2y=68
Y= 34

CHECKING Answer ($34 being the cost of the adult ticket) y = (134-3*22)/2

3*$22 + 2*$34 = $66 + $68 = $134

8 0

2 years ago