Complete Question:
Find the resistance of a wire of length 0.65 m, radius 0.25 mm and resistivity 3 * 10^{-6} ohm-metre.
Answer:
Resistance = 9.95 Ohms
Explanation:
<u>Given the following data;</u>
Length = 0.65 m
Radius = 0.25 mm to meters = 0.00025 m
Resistivity = 3 * 10^{-6} ohm-metre.
To find the resistance of the wire;
Mathematically, resistance is given by the formula;
Where;
- P is the resistivity of the material.
- L is the length of the material.
- A is the cross-sectional area of the material.
First of all, we would find the cross-sectional area of the wire.
Area of circle = πr²
Substituting into the equation, we have;
Area = 3.142 * (0.00025)²
Area = 3.142 * 6.25 * 10^{-8}
Area = 1.96 * 10^{-7} m²
Now, to find the resistance of the wire;
<em>Resistance = 9.95 Ohms </em>
Answer:
A
Explanation:
its A because your comparing so comparative
The answer is B. One plate slides past another.
The San Andreas Fault in California and the Alpine Fault in New Zealand are examples of transform boundaries.
Hope this helps! :)
The x- and y-coordinates are 9142.57 m and -304.425 m
<u>Explanation:</u>
As the motion of the shell is in a plane (two dimensional space) and the acceleration is that due to gravity which is vertically downward, we resolve initial velocity of the shell in horizontal and vertical directions. If the initial velocity of the shell is making angle with the horizontal, the horizontal component of initial velocity will be
As the acceleration of the shell is vertical having no horizontal component, the shell may be considered to move horizontally with constant velocity of and hence the horizontal distance covered (or the x coordinate of the shell with point of projection as origin) is given by
For motion with constant acceleration, we know
Along the horizontal, x-axis, we might write this as
Measuring distances relative to the firing point means
we know that,
or,
By applying the values, we get,
The acceleration of gravity is vertically downward and is , hence the vertical distance covered (or y coordinate of the shell) is given by the second equation of motion
we know, and , so,
y = 11701.8 - 4.9(2450.25)= 11701.8 - 12006.225 = - 304.425 m
Am sorry what can you be more specific