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2 years ago

Helppppp pleaseee :)

Mathematics

1 answer:

Sedaia [141]2 years ago

6 0

Answer:

I need to see letter P first mate XD

Step-by-step explanation:

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Whats the answer for (5x + 8)(4x² + 6x - 8)

mestny [16]

$(5x + 8)(4x^2 + 6x - 8)\\ \\ 5x(4x^2 + 6x - 8) + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 32x^2 + 48x - 64 \\ \\ 20x^3 + (30x^2 + 32x^2) + (-40x + 48x) - 64 \\ \\ 20x^3 + 62x^2 + 8x - 64 \\ \\$

The final result is: 20x^3 + 62x^2 + 8x - 64.

4 0

2 years ago

I WILL LITERALLY GIVE OUT 50 POINTS FOR THIS!!!!

kaheart [24]

Answer: B) -3

Step-by-step explanation:

X<-11/3 if u divide -11/3 = is about -3.6666

3 0

2 years ago

Read 2 more answers

Which of the following ratios is equivalent to 24:36?

Ksju [112]

Answer:

D, 20:30

Step-by-step explanation:

At first glance, this does not seem like the correct ratio. But I'll spare you a long intro and get into it:

20:30: Divide both of them by 10

=2:3

2 x 12:3 x 12

24:36

Hope this helps!

4 0

2 years ago

Find the volume of a cone with a base radius of 6 yd and a height of 12 yd

anygoal [31]

Answer:

452.38934 yd^3

Step-by-step explanation:

5 0

2 years ago

Solve this x²+8/10 -x = 10/2

AysviL [449]

$x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\


$
$x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\
x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\$

7 0

2 years ago