T/0.3 = 1.7/0.9 ( the one I'm pointing at)
1 answer:
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Answer:
0.7
Step-by-step explanation:
The Probability of Chips in Urn 1
P(R) = 3/4
P(W) = 1/4
The Probability of Chips in Urn 2
P(R) = 1/2
P(W) = 1/2
The problem can be solved using probability tree method. The probability tree of the given question is attached with the answer.
The Probability tree shows the exchange of chips firstly and then the final probability of Red Chips and White Chips in Urn 1.
To find the final answer we can sum up the probabilities of the branches which are ticked in the diagram.
Probability of Branch 1 (ticked in diagram)
3/4 x 3/5 x 3/4 = 0.3375
Probability of Branch 2 (ticked in diagram)
3/4 x 2/5 x 2/4 = 0.15
Probability of Branch 3 (ticked in diagram)
1/4 x 2/5 x 1 = 0.1
Probability of Branch 4 (ticked in diagram)
1/4 x 3/5 x 3/4 = 0.1125
Final Probability = 0.3375 + 0.15 + 0.1 + 0.1125
= 0.7 Answer
Answer:
The 95% confidence interval to estimate the true proportion of evens rolled on a die is (0.2842, 0.6758). This means that we are 95% sure that for the entire population of dies, the true proportion of evens rolled on a die is between 0.2842 and 0.6758
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
95% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval to estimate the true proportion of evens rolled on a die is (0.2842, 0.6758). This means that we are 95% sure that for the entire population of dies, the true proportion of evens rolled on a die is between 0.2842 and 0.6758