The equation that can be used to model the situation regarding the e-books and paperback is 5x + 12y = 68
The following information can be gotten from the question:
Total amount spent on e-books and paperback = $68
<em>Cost</em><em> of e-book = $5 each.</em>
<em>Cost of paperback = $12 each</em>
<em>Number of</em><em> e-books</em><em> = x</em>
<em>Number of paperbacks = y</em>
Therefore, the equation that can be used to model the situation regarding the <em>e-books </em>and <em>paperback</em> will be:
= 5(x) + 12(y) = 68
5x + 12y = 68
The equation will be 5x + 12y = 68
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Answer:
Point slope is ( Y+4) = 1/2(x+3)
Slope intercept is Y = 1/2(x) -5/2
Step-by-step explanation:
For the point slope form.
Given the point as (-3,-4)
And the gradient m = 1/2
Point slope form is
(Y - y1) = m(x-x1)
So
X1 = -3
Y1 = -4
(Y - y1) = m(x-x1)
(Y - (-4)) = 1/2(x -(-3))
( Y+4) = 1/2(x+3)
For the slopes intercept form
Y = mx + c
We can continue from where the point slope form stopped.
( Y+4) = 1/2(x+3)
2(y+4)= x+3
2y + 8 = x+3
2y = x+3-8
2y = x-5
Y = x/2 - 5/2
Y = 1/2(x) -5/2
Where -5/2 = c
1/2 = m
The answer is A!
-4.82, -4(2/3) = - 4.667, sqrt 15 is 3.873, 4.15, 465% is 4.65, and 1.5pi =4.65
Hope this helps!
Assume uniformly accelerated motion
Vf = Vo - at => a= [Vo - Vf] / t
Vf = 0, t = 20 s => a = Vo / 20
x = Vot - at^2 / 2
x = Vot - (Vo / 20) * t^2 /2
x = 1775 feet * [1 mile / 5280 feet] = 0.336 mile
t = 20 s
=> 0.336 = 20Vo - Vo(20)^2 /(40) = 20Vo - 10 Vo = 10 Vo
=> Vo = 0.336 /10 = 0.0336 mile /s
Vo = 0.0336 mile/s * 3600 s/h = 120.96 mile / h
Therefore, the car was way over the speed limit.
Answer:
D
Step-by-step explanation:
25+30= time Layla spent. 3x time layla spent = elijah's time