2*2-1/3 yards= 4-2/ yards =14 feet.
THE SHADOW IS HALF THE HEIGHT OF OBJECT, SINCE A 6 FEET BOY CASTS A 3 FEET . SO THE POLE WILL BE TWICE THE LENGTH OF ITS SHADOW. try this
Answer:
Part 1) The length of the longest side of ∆ABC is 4 units
Part 2) The ratio of the area of ∆ABC to the area of ∆DEF is
Step-by-step explanation:
Part 1) Find the length of the longest side of ∆ABC
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor
The ratio of its perimeters is equal to the scale factor
Let
z ----> the scale factor
x ----> the length of the longest side of ∆ABC
y ----> the length of the longest side of ∆DEF
so
we have
substitute
solve for x
therefore
The length of the longest side of ∆ABC is 4 units
Part 2) Find the ratio of the area of ∆ABC to the area of ∆DEF
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z ----> the scale factor
x ----> the area of ∆ABC
y ----> the area of ∆DEF
we have
so
therefore
The ratio of the area of ∆ABC to the area of ∆DEF is
Step-by-step explanation:
substitute the given value in the standard form equation. it will give you the slope intercept form
<h3>(1136+1272)-(1138+{-1250})</h3><h3>=2408-(-112)</h3><h3>=2408+112</h3><h3>=2520</h3><h3>the answer is 2520</h3><h2 /><h2 /><h2>hope it helped :-)</h2>
Assuming you want them multiplied
f(x)*g(x)=(3x+5)(x^2)=3x³+6x²