Answer: 2 / 3 = 0.666666666667
First, determine the number of computers that are needed for 924 students.
n = (924 students)(5 computers / 12 students)
n = 385 computers
Since, there are only 125 computers, the difference can be calculated.
d = 385 computers - 125 computers
d = 260 computers
Hence, 260 more computers are still needed.
T^2 = A^3
T^2 = 2^3
T^2 = 8
Time = sq root (8)
Time =
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2.8284271247
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29) Turns is the ratio of annual amount to average amount.
Cost turns = 57,982.85/15,545 ≈ 3.73
Sales turns = 130,935.60/35,388 ≈ 3.70
30) Consider January of the following year to be month 13.
7/16 to 13/14 is 6 months less 2 days. There are 31 days in July, August, October, and December, so 4 more days than 30 days per month. The total number of days is 6*30 -2 +4 = 182
31) I = Prt = $5380×0.118333×90/360 = $159.16
