Triangle RTS is congruent to RQS by AAS postulate of congruent
Step-by-step explanation:
Let us revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles
and one side in the 2nd Δ
- HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right Δ
∵ SR bisects angle TSQ ⇒ given
∴ ∠TSR ≅ ∠QSR
∴ m∠TSR ≅ m∠QSR
∵ ∠T ≅ ∠Q ⇒ given
∴ m∠T ≅ m∠Q
In two triangles RTS and RQS
∵ m∠T ≅ m∠Q
∵ m∠TSR ≅ m∠QSR
∵ RS is a common side in the two triangle
- By using the 4th case above
∴ Δ RTS ≅ ΔRQS ⇒ AAS postulate
Triangle RTS is congruent to RQS by AAS postulate of congruent
Learn more:
You can learn more about the congruent in brainly.com/question/3202836
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Answer:
As shown below
Step-by-step explanation:
Given that when X denotes the errors in an experimental transmission channel, when checked by a certifier that detects missing pulses. follows the cumulative density function as given below:
Don’t listen to the people who give you the links
No, he forgot to add the area of the triangles to the area of the rectangle.
It is said that Jeremy thought he solved for the area of the whole parallelogram correctly by multiplying the base and height of the rectangle, which is just a part of the whole parallelogram.
Jeremy’s answer is incomplete, he only calculated the area of the triangle as the answer.
This is because one way of finding an area of a parallelogram is dividing the shape into a rectangle with a triangle on each side.
The real area of the parallelogram is 70 cm^2
(with areas of each triangles added)
With that being said, the formula of a parallelogram that is said is:
A = bh
Which means a height perpendicular to the base of the whole paralleogram.
Answer:
80/81
Step-by-step explanation:
hope this helps!