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2 years ago

5

Darius takes his family on an afternoon boat ride. Going through york canal, he drives 5 miles in 15 minutes. Later on as he cro

sses stover lake, he drives 30 minutes at the same average speed. Which statement about the distance is true? A is: The distance traveled in york canal is 15 miles less than the distance traveled on stover lake. B is: The distance in york canal is twice the distance traveled on stover lake. C: The distance traveled in york canal is one half the distance traveled on stover lake. D: The distance traveled in york canal and stover lake are the same.

1 answer:

Arisa [49]2 years ago

3 0

C- the distance traveled in York canal is one half the distance traveled on strover lake

-HOPE IT HELPS

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What is 6-2p=p+9 ?Because I don't know it

nikklg [1K]

Hey there!

Firstly, you have to $\bold{simplify}$ each of the sides of your equation
$\bold{6-2p-p+9\downarrow}$
$\bold{6+(-2p)=p+9\downarrow}$
$\rightarrow\bold{-2p+6=p+9}$
Now that you have that portion out of the way, we could move on to our second step... which is to $\bold{subtract}$ by the value of $\bold{p}$ on each of your sides
$\bold{-2p+6-p-p+9-p\downarrow}$
$\rightarrow\bold{-3p+6-9}$ (you get this because we solve the particular equation we added above)
Thirdly, you have to $\bold{subtract}$ by the number $\bold{6}$ on each of your sides
$\bold{-3p+6-6=9-6\downarrow}$
$\bold{Cancel:6-6}$ because it equals to $\bold{0}$
$\bold{Keep:9-6}$ because it brings us closer and closer to the answer of $\bold{p}$
Fourthly, we have to $\bold{divide}$ by the number $\bold{-3}$ on each of your sides
$\bold{\frac{-3p}{-3}=\frac{3}{-3}}$
$\boxed{\boxed{\bold{Answer:p=-1}}}$ $\checkmark$

Good luck on your assignment and enjoy your day!

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8 0

2 years ago

The area of a rectangle is 63m^2 and the length of the rectangle is 11m more than twice the width. Find the length and width.

AleksandrR [38]

Answer:

width = 3.5 m

length = 18 m

Step-by-step explanation:

area = length x width

x is the width then length = 2x + 11

x(2x + 11) = 63

2x^2 + 11x - 63 = 0

The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a

with a = 2

b = 11

c = -63

substitute in the formula

x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)

x = [-11 +/- √(121 + 504)]/4

x = [-11 +/- √625]/4

x = (-11 +/- 25)/4

x1 = (-11 + 25)/4 = 14/4 = 3.5

x2 = (-11 - 25)/4 = -36/4 = -9

since width can't be a negative number, x is 3.5

length = 2x + 11 = 2(3.5) + 11 = 18

7 0

1 year ago

For the problem below Define a variable write an equation and solve it use the 5D process if needed to help you set up your equa

Mariulka [41]

D=# of tickets sold at the door
a=# of tickets sold in advance

3a+5d=2630
d=a+30

3a+5(a+30)=2630
8a+150=2630
8a=2480
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310 tickets were sold in advance and 340 tickets were sold at the door.

5 0

2 years ago

40 pts and Brainliest pls give detailed answer :)

horsena [70]

Answer:

58 ft

Step-by-step explanation:

So I attached a diagram that illustrates the triangle that is formed. We know an angle, as well as the hypotenuse. We are looking for the height, or in other words the opposite side of the angle. There is a trigonometric function defined as: $sin(\theta) = \frac{opposite}{hypotenuse}$ . Using this we can plug in known values and solve for the opposite side, which I'll simply represent as x.

$sin(46) = \frac{x}{80}$

Multiply both sides by 80

$sin(46) * 80 = x$

Calculate sin(46) using a calculator (make sure it's in degree mode)

$0.7193398 * 80 = x$

Simplify

$57.547 \approx x$

Round this to the nearest foot

$58 \approx x$

4 0

1 year ago

Help me quickkkk!!<br> A = 1/2(a+b)h solve for b

nasty-shy [4]

Answer:

2A/h - a = b

Step-by-step explanation:

Using A= 1/2(a+b)h

Divide both side by h

⇒A/h = 1/2(a + b)

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⇒2A/h = a + b

Take the 2 over to the other side

2A/h - a = b

Keep in mind, that the (a) is not on the bottom, rather on its own

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2 years ago