Answer:
111.15 g are required to prepare 500 ml of a 3 M solution
Explanation:
In a 3 M solution of Ca(OH)₂ there are 3 moles of Ca(OH)₂ per liter solution. In 500 ml of this solution, there will be (3 mol/2) 1.5 mol Ca(OH)₂.
Since 1 mol of Ca(OH)₂ has a mass of 74.1 g, 1.5 mol will have a mass of
(1.5 mol Ca(OH)₂ *(74.1 g / 1 mol)) 111.15 g. This mass of Ca(OH)₂ is required to prepare the 500 ml 3 M solution.
Answer:
The second answer choice
Explanation:
X seems to list attributes for opaque objects, and y lists attributes of Transparent objects.
Answer:
Los metaloides serían los elementos con propiedades intermedias. No existe una definición estandarizada de elemento metaloide ni un consenso completo sobre los elementos que son metaloides. A pesar de la falta de especificidad en el término, es muy utilizado en los textos químicos, tanto educativos como divulgativos o de investigación.
Explanation:
Answer:
The pH of the buffer solution is 4.60.
Explanation:
Concentration of acid = ![[HC_2H_3O_2]=0.225 M](https://tex.z-dn.net/?f=%5BHC_2H_3O_2%5D%3D0.225%20M)
Concentration of salt = ![[KC_2H_3O_2]=0.162 M](https://tex.z-dn.net/?f=%5BKC_2H_3O_2%5D%3D0.162%20M)
Dissociation constant = 
The pH of the buffer can be determined by Henderson-Hasselbalch equation:
![pH=pK_a+\log\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
![pH=-\log[1.8 \times 10^{-5}]+\log\frac{0.162 M}{0.225 M}](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B1.8%20%5Ctimes%2010%5E%7B-5%7D%5D%2B%5Clog%5Cfrac%7B0.162%20M%7D%7B0.225%20M%7D)
pH = 4.60
The pH of the buffer solution is 4.60.
