Answer:
Incidence of cystic fibrosis on the island= 0.0025
Explanation:
According to the given information, the population is in Hardy Weinberg equilibrium which means that the allele frequencies would be maintained over generations.
Given that total population size is = 20
Total number of alleles = 20 x 2 = 40 (since human are diploid, each individual has two alleles for one gene).
Out of total 19 people, only two are heterozygous for cystic fibrosis which means that out of total 40 alleles, the number of recessive allele for cystic fibrosis is = 2
Frequency of recessive allele (q)= 2/ 40 = 0.05
Frequency of cystic fibrosis genotype (q^2) = 0.05 x 0.05 = 0.0025
Therefore, incidence of cystic fibrosis on the island would be = 0.0025