Answer:
10.85 g of H2O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
NaOH + HCl —> NaCl + H2O
Next, we shall determine the mass of NaOH that reacted and the mass of H2O produced from the balanced equation.
These can be obtained as illustrated below:
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Mass of NaOH from the balanced equation = 1 × 40 = 40 g
Molar mass of H2O = (2×1) + 16 = 2 + 16 = 18 g/mol
Mass of H2O from the balanced equation = 1 × 18 = 18 g
Summary:
From the balanced equation above,
40 g of NaOH reacted to produce 18 g of H2O.
Finally, we shall determine the mass of water, H2O produced from the reaction as follow:
From the balanced equation above,
40 g of NaOH reacted to produce 18 g of H2O.
Therefore, 24.1 g of NaOH will react to produce = (24.1 × 18)/40 = 10.85 g of H2O.
Therefore, 10.85 g of H2O were produced from the reaction.